To find the largest 4 digit number divisible by 4, 7 and 13, we find the LCM of 4, 7 and 13 first. LCM(4, 7, 13) = 4 × 7 × 13 = 364 Now, to we divide 9999 by 364 and subtract the remainder from 9999 to get the number completely divisible by 4, 7 and 13. 9999-171 = 9828 Because the number leaves the remainder 3, so we add 3 to 9828. Therefore
Given three numbers, our task is to find the largest number by which when given 3 numbers are divided leads to same remainder. It may be assumed that all given numbers are given in increasing order. Examples:
Which is the largest 4 digit number divisible by 2 and 3? ANSWER: The number is 9996. 9996 is the greatest 4-digit number that is divisible by 2 and 3. Which is the smallest 4 digit number divisible by both 2 and 3?
Q10. Eleven friends spent Rs. 18 each on a tour and the twelfth friend spent Rs. 11 less than the average expenditure of all twelve of them. What is the total money spent by twelve friends? Calculation : Largest 4-digit number = 9999 Smallest 3-digit number = 100 Required difference = 9999 – 100 ⇒ 9899 ∴ The di.
The difference between the greatest and the smallest 4 digit numbers that can be formed by the digits 5, 3, 0 and 8 such that 5 is always at ones place and number digits are repeated is
Largest number formed by sum and product of digits. Given a range, say 0 − 100 0 − 100, what is the largest number formed by both adding or multiplying the digits? The answer here is 9 ∗ 9 9 ∗ 9, actually 9n 9 n, where n is the number of zeros in the upper range. So, for 100 − 10000 100 − 10000 the largest is 9 ∗ 9 ∗ 9 ∗ 9 9
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4 digit largest number
